Question

pls answer this question with full explanation.good answers will be marked as brainiest..▪︎▪︎▪︎​

Answer 1

given polynomial p(x)= ax³+3x²-13 and 2x²-5x+a is divide by x-2 get same remainder

then x-2=0 or x=2

p(x)=ax³+3x²-13

replace x by 2 we get

p(2)=a(2)³+3(2)²-13

p(2)= 8a+12-13

p(2)=8a-1

2x²-5x+a

replace x by 2 we get

q(2)=2(2)³-5(2)+a

q(2)=16-10+a

q(2)=6+a

Given remainder is same

8a-1=6+a

8a-1+1-a=6+a+1-a

7a=7

a=1