Pls answer this Question with full explanation plz
Answers
The equation for the reaction between the sodium bicarbonate and acetic acid is given below:
NaHCO₃ + CH₃COOH = CH₃COONa + H₂O + CO₂
The law of conservation of mass states that the mass of the reactants is equal to the mass of the products.
Mass of reactants = 20 + 8.4 = 28.4g
Mass of CO₂ produced = 4.4 g
28.4 - 4.4 = 24g
That means mass of the water and sodium acetate formed is 24 g
Use mole ratio to find the mass of the sodium acetate formed
Mole ratio in the equation is 1:1:1:1:1
Find moles of sodium 8.4 g bicarbonate
moles = mass/molar mass
molar mass = 84
moles= 8.4/84
=0.1 moles
Since ratio is 1:1, then the moles of the H₂O is also 0.1
Find mass of water formed
Mass = moles × molar mass
= 0.1 × 18
= 1.8 g
Mass of sodium acetate
mass = moles × molar mass
= 0.1 × 82
= 8.2 g
In this equation the sodium bicarbonate is a limiting reagent hence, it will still be present in the reactants.
Answer:
✳️The equation for the reaction between the sodium bicarbonate and acetic acid is given below:
✳️NaHCO₃ + CH₃COOH = CH₃COONa + H₂O + CO₂
✳️The law of conservation of mass states that the mass of the reactants is equal to the mass of the products.
✳️Mass of reactants = 20 + 8.4 = 28.4g
✳️Mass of CO₂ produced = 4.4 g
✳️28.4 - 4.4 = 24g
✳️That means mass of the water and sodium acetate formed is 24 g
✳️Use mole ratio to find the mass of the sodium acetate formed
✳️Mole ratio in the equation is 1:1:1:1:1
✳️Find moles of sodium 8.4 g bicarbonate
✳️moles = mass/molar mass
✳️molar mass = 84
✳️moles= 8.4/84
✳️=0.1 moles
✳️Since ratio is 1:1, then the moles of the H₂O is also 0.1
✳️Find mass of water formed
✳️Mass = moles × molar mass
= 0.1 × 18
= 1.8 g
✳️Mass of sodium acetate
✳️mass = moles × molar mass
= 0.1 × 82
= 8.2 g
✳️In this equation the sodium bicarbonate is a limiting reagent hence, it will still be present in the reactants.