pls answer this quickly
Answers
Answer:
Given Data is: 59, 62, 65, x, x + 2, 72, 85 and 94.
Need to find: The value of x.
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\underline{\bf{\dag} \:\mathfrak{As\;we\;know\: that\: :}}
†Asweknowthat:
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The formula of Median for even terms is given by :
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\star\;\boxed{\sf{\pink{Median = \dfrac{\bigg(\dfrac{n}{2} \bigg)^{th} \; observation + \bigg(\dfrac{n}{2} + 1\bigg)^{th} \; observation}{2}}}}⋆
Median=
2
(
2
n
)
th
observation+(
2
n
+1)
th
observation
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Here, nth term is even that is 8 and Median is 69.
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Now,
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\begin{gathered}:\implies\sf Median = \dfrac{\dfrac{\cancel{\;8}}{\cancel{\;2}} \; observation + \bigg(\dfrac{8}{2}^{th} + 1 \bigg)^{th} \; observation}{2} \\\\\\:\implies\sf 69 = \dfrac{4^{th} \; observation + 5^{th}\; observation}{2} \\\\\\:\implies\sf 69 = \dfrac{x + x + 2}{2} \\\\\\:\implies\sf 138 = 2x + 2 \\\\\\:\implies\sf 2x = 138 - 2 \\\\\\:\implies\sf 2x = 136 \\\\\\:\implies\sf x = \cancel\dfrac{136}{2} \\\\\\:\implies{\underline{\boxed{\frak{\pink{x = 68}}}}}\;\bigstar\end{gathered}
:⟹Median=
2
2
8
observation+(
2
8
th
+1)
th
observation
:⟹69=
2
4
th
observation+5
th
observation
:⟹69=
2
x+x+2
:⟹138=2x+2
:⟹2x=138−2
:⟹2x=136
:⟹x=
2
136
:⟹
x=68
★
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\therefore{\underline{\sf{Hence, \; the \; required \; value \; of \; x \; is \; \bf{ 68}.}}}∴
Hence,therequiredvalueofxis68.
Explanation:
this is your correct answer
