pls answer this trignometry question!
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formula used:
cosec²x - cot²x = 1
hope you like....
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hope it helps.....
cosec²x - cot²x = 1
hope you like....
"""""""""""""""""""""
hope it helps.....
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Answered by
1
Hi ,
here I used A instead Alfa
LHS = 1/(cosecA+cotA) - 1/sinA
= ( cosecA-cotA)/(cosec²A- cot²A ) - cosecA
= cosecA-cotA -cosecA
= -cotA-----( 1 )
RHS = 1/sinA - 1/( cosecA-cotA)
= cosecA - ( cosecA+cotA) /(cosec²A- cot²A )
= cosecA - (cosecA + cotA)
= cosecA - cosecA - cotA
= - cotA ---( 2 )
Therefore ,
from ( 1 ) and ( 2),
LHS = RHS
I hope this helps you.
:)
here I used A instead Alfa
LHS = 1/(cosecA+cotA) - 1/sinA
= ( cosecA-cotA)/(cosec²A- cot²A ) - cosecA
= cosecA-cotA -cosecA
= -cotA-----( 1 )
RHS = 1/sinA - 1/( cosecA-cotA)
= cosecA - ( cosecA+cotA) /(cosec²A- cot²A )
= cosecA - (cosecA + cotA)
= cosecA - cosecA - cotA
= - cotA ---( 2 )
Therefore ,
from ( 1 ) and ( 2),
LHS = RHS
I hope this helps you.
:)
mysticd:
here I used A instead of alfa
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