Question

pls answer this very urgent

Answer 1

Answer:

There is a slight mistake it is sec theta + csc theta = q

Step-by-step explanation:

p=sinθ+cosθ and q=secθ+cosecθ

q(p²-1)

=(secθ+cosecθ)[(sinθ+cosθ)²-1]

=(1/cosθ+1/sinθ)(sin²θ+2sinθcosθ+cos²θ-1)

={(sinθ+cosθ)/sinθcosθ}(2sinθcosθ) [ Since, sin²θ+cos²θ=1]

=2(sinθ+cosθ)

=2p (Proved

Answer 2

Answer:

Step-by-step explanation:

p=sinθ+cosθ and q=secθ+cosecθ

q(p²-1)

=(secθ+cosecθ)[(sinθ+cosθ)²-1]

=(1/cosθ+1/sinθ)(sin²θ+2sinθcosθ+cos²θ-1)

={(sinθ+cosθ)/sinθcosθ}(2sinθcosθ) [ Since, sin²θ+cos²θ=1]

=2(sinθ+cosθ)

=2p (Proved

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