Question

pls answer this with clear step by step explaination​

Answer 1

Given :

• Sides of a triangle are 41 m , 40 m and 9 m .

To Find :

• Area of Trinagular Field .

Solution :

• a = 41 m
• b = 40 m
• c = 9 m

$\longmapsto\tt{s=\dfrac{a+b+c}{2}}$

$\longmapsto\tt{\dfrac{40+41+9}{2}}$

$\longmapsto\tt{\cancel\dfrac{90}{2}}$

$\longmapsto\tt\bf{45\:m}$

Now ,

$\longmapsto\tt{\sqrt{s(s-a)(s-b)(s-c)}}$

$\longmapsto\tt{\sqrt{45(45-41)(45-40)(45-9)}}$

$\longmapsto\tt{\sqrt{45(4)\:(5)\:(36)}}$

$\longmapsto\tt{\sqrt{3\times{3}\times{5}\times{2}\times{2}\times{5}\times{3}\times{3}\times{2}\times{2}}}$

$\longmapsto\tt{3\times{5}\times{2}\times{3}\times{2}}$

$\longmapsto\tt\bf{180\:{cm}^{2}}$

So , The Area of Triangular Field is 180 cm² ...