Pls answer this with written answer.
Answers
Step-by-step explanation:
1. Given 3 sides of triangle = 14 cm 17cm and 25cm
Perimeter = 14+17 + 25 = 56 cm
2. Perimeter of side given = 40cm
side 1 = 12.9 cm
side 2 = 14.6cm
Side 3 = 40-(12.9+14.6) =40 - 27 .5 cm = 12.5cm
3i) L = 25 B = 18 P = 2(L+B ).= 2(43) = 86cm
ii) L = 27 cm B = 17cm P = 2(L+B) = 2(27+17) = 44×2 = 88cm
iii) L = 7.2 m B = 80cm = 80/100 = 0.8 m
P = 2(L+ B) = 2(7.2 +0.8) =8 .0 × 2 = 1.6m
4. Side of square field = 9m
Perimeter = 4× side = 4× 9 = 36m
Area = side × side = 9×9 =81 sq m.
5. area of square = 265 cm^2
side ^2 = 256
side = root(256) = 16 cm
Perimeter = 4 × side = 4×16 = 64 cm
6. Area of rectangle = 768m^2
length = 32
breadth = 768/32 = 96/4 = 24 m
P = 2(32 + 24) = 56×2 = 112m
1m cost = 20 × 112 = Rs 2240
7. Area of rectangular field = 3400 m^2length = 68 m
breadth = 3400/68 = 200/4 = 50m
P =2(L+B) = 2(50+68) = 118 ×2 = 236m
One round = 236m
5 rounds = 236×5 = 1180m covered
8. Area of rec park = 4100m^2
breadth = 50m
Length = 4100/50 = 410/5 = 82m
P = 2(82+50) = 2× 132 = 264m
Cost of fencing of 1m = 30
264 m costs = 264 × 30 = 7920