Question

Pls answer thse questions will mark as BRAINLIEST if helped. Pls show working and all the steps

Answer 1

26. Sum of $\frac{65}{12 } \: \: and \: \: \frac{8}{3}$

$= \frac{65}{12} + \frac{8}{3} \\ \\ = > \frac{65 + 8(4)}{12} \\ \\ = \frac{65 + 32}{12} \\ \\ = \frac{97}{12}$

Difference of

$\frac{65}{12} \: and \: \frac{8}{3} \\ \\ \\ = \frac{65}{12} - \frac{8}{3} \\ \\ = \frac{65 - (8(4))}{12} \\ \\ = \frac{65 - 32}{12} \\ \\ = \frac{33}{12}$

So, Dividing sum by the difference.

$\frac{97}{12} \div \frac{33}{12} \\ \\ = > \frac{97}{ \cancel12} \times \frac{ \cancel12}{33} = \boxed{ \red{\frac{97}{33}} }$

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27.

The cost of 2 1/2 metre of cloth is Rs 78 3/4

$2 \frac{1}{2} = \frac{5}{2} \\ \\ and \\ \\ 78 \frac{3}{4} = \frac{315}{4}$

So, The cost of 1 m of cloth

$= \frac{315}{4} \div \frac{5}{2} \\ or \\ = \frac{ \frac{315}{4} }{ \frac{5}{2} } \\ \\ \implies \: \frac{315}{4} \times \frac{2}{5} = \frac{63}{2} \\ \\ \implies \boxed{\red{ \frac{63}{2}}}$

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28. Given that, product of two rational numbers is 10 and one of them is -8.

So let the other number be x

=> -8 × x = 10

$= > x = \frac{10}{ - 8} \\ \\ = > \boxed {\red{ - \frac{5}{4} }}$

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29.

Given that, 24 trousers are prepared with 54 m of cloth.

i.e. Length required to make 24 trousers = 54 m

So, length required to make each pair of trouser = $\frac{54}{24} \: m$

$= \boxed{ \red{ \frac{9}{4} m}}$

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30.

We are given that,

He donated 1/5th part of his salary to an NGO

This means, $\frac{x}{5}$

is the amount given to NGO

Similarly

$\frac{x}{4} = > \: for \: food$

$\frac{x}{3} = > \: on \: rent$

$\frac{x}{15} = > on \: other \: expenses$

Amount left => 9000

Now,

Let Rohit's salary be x

So, according to the question

$\small \: x = \frac{x}{5} + \frac{x}{4} + \frac{x}{3} + \frac{x}{15} + 9000 \\ \\ = > \scriptsize x = \frac{12x + 15x + 20x + 4x + 540000}{60} \\ \\ = > 60x = 51x + 540000 \\ \\ = > 60x - 51x = 540000 \\ \\ = > 9x = 540000 \\ \\ = > x = \frac{540000}{9} \\ \\ = > x= \boxed{ \red{60000}}$

The monthly income of Rohit is Rs 60,000