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Numbers- 25,85,135
Remainder left- 5
Therefore, the actual numbers are-
(25-5),(85-5),(135-5)
= 20,80,130
Now find the HCF(20,80,130)
HCF(20,80,130) = 10
Remainder left- 5
Therefore, the actual numbers are-
(25-5),(85-5),(135-5)
= 20,80,130
Now find the HCF(20,80,130)
HCF(20,80,130) = 10
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