Question

pls answer to this question ​

Answer 1

Answer:

$x = \frac{5}{7}$ Might Help THANKS!!!!!!!!!

Step-by-step explanation:

$(4)^{x-1}\times(0.5)^{3-2x} = (\frac{1}{8})^{x}\\\\((2)^{2})^{x-1} \times (\frac{1}{2})^{3-2x} = (\frac{1}{2^{3}})^{x}\\\\2^{2x-2} \times 2^{(3-2x)(-1)} = 2^{(-3)(x)}\\\\2^{(2x-2)+(2x-3)} = 2^{-3x}\\\\2^{4x-5} = 2^{-3x}\\\\4x-5 = -3x\\\\7x = 5\\\\x = \frac{5}{7}$