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x=70 ( alt. Int. <)
y=60 (""""""""""")
z=50(<s sum property of triangle)
y=60 (""""""""""")
z=50(<s sum property of triangle)
abi12345:
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Given : AB || CD
Angle A = 70°
Angle C = 60°
To find : Angle x, angle y, angle Z
Finding :
AB || CD and AD as transversal
Angle x = Angle A ....... (Alternate Interior angle property)
Therefore, Angle X = 70°...........(I)
Again,
AB || CD and BC as transversal
Angle y = Angle B ....... (Alternate Interior angle property)
Hence, Angle Y = 60°............(II)
Now in ∆AOB,
Angles AOB + OBA + BOA = 180°. (sum of all angles in a triangle)
Z + Y + 70° = 180°
Z + 60 + 70 = 180......(from equation II)
Z = 180 - (70 + 60)
Z = 180 - 130
Z = 50°...........(III)
So equation (I), (II) and (III) make up your answer.
Hope it'll help... :-D
Angle A = 70°
Angle C = 60°
To find : Angle x, angle y, angle Z
Finding :
AB || CD and AD as transversal
Angle x = Angle A ....... (Alternate Interior angle property)
Therefore, Angle X = 70°...........(I)
Again,
AB || CD and BC as transversal
Angle y = Angle B ....... (Alternate Interior angle property)
Hence, Angle Y = 60°............(II)
Now in ∆AOB,
Angles AOB + OBA + BOA = 180°. (sum of all angles in a triangle)
Z + Y + 70° = 180°
Z + 60 + 70 = 180......(from equation II)
Z = 180 - (70 + 60)
Z = 180 - 130
Z = 50°...........(III)
So equation (I), (II) and (III) make up your answer.
Hope it'll help... :-D
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