Question

pls.... answer very fast I need answer of this question plz.plz.plz.

Answer 1

√ 3*(sin x/cos x) = 3 sin x
>> cos x = √3/3= 1/√3
$\ { \sin(x ) }^{2} - { \cos(x) }^{2} \\ = 1 - { \cos(x) }^{2} - { \cos(x) }^{2} \\ = 1 - 2 { \cos(x) }^{2}$
= 1-2(1/√3)^2 = 1-2/3 =1/3

Answer 2

Here,
Is your answer
Thanks