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Answer:
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Step-by-step explanation:
now let the required trapezium be abcd
wherein bc and ad are two parallel sides ie requied bases of it such that bc is longer base and ad is shorter base.
also ab is its height such that ab perpendicular to bc and ad ie angle abc and angle bad are 90 degree each
so according to first condition
bc=5ad (1)
according to the second condition
ab=ad-1 (2)
so here area of trapezoid=90 unit.square
so we know that
area of trapezoid=1/2×[sum of length of parallel sides]×height
thus 90=1/2×(bc+ad)×ab
=1/2×(5ad+ad)×(ad-1) from (1) and (2)
=6ad(ad-1)/2
=6ad square-6ad/2
ie 6ad square-6ad=180
so dividing by 3 on both sides
we get
ad square-ad=30
so ad square-ad-30=0
ie ad square-6ad+5ad-30=0
so ad(ad-6)+5(ad-6)=0
ie (ad-6)(ad+5)=0
so ad=6 or ad=-5
but as dimensions length of any geometric figure are never negative
ad=-5 is absurd
thus ad=6 units
so substitute value of ad in (1) and (2)
we get bc=30
ab=5
hence length of shorter base is 6 units