Math, asked by anandhtvcnkl, 1 month ago

pls answer with explanation​

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Answered by Anonymous
3

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\longrightarrow \sf \cos \theta =  \frac{ \sqrt{3} }{2} \\  \\ \longrightarrow \sf\cos \theta =  \cos 30 \degree \\  \\\longrightarrow \sf \theta = 30 \degree

Now

\longrightarrow \sf4 { \sin}^{2} \theta +  { \tan}^{2} \theta \\  \\\longrightarrow \sf 4 { \sin}^{2}30+  { \tan}^{2}30 \\  \\ \longrightarrow \sf4 \times  \bigg(\frac{1}{2}  {\bigg)}^{2} +  {\bigg( \frac{1}{ \sqrt{3}  }\bigg) }^{2} \\  \\\longrightarrow \sf 4 \times  \frac{1}{4} +  \frac{1}{3} \\  \\ \longrightarrow \sf1 +  \frac{1}{3} \\  \\\longrightarrow \sf  \frac{3 + 1}{3} \\  \\ \longrightarrow \sf \frac{4}{3}

Option ( d ) is correct

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