Question

Pls answer with explanation it will help a lot.​

Answer 1

Hey army I guess your bias is Tae

Answer 2

$\huge \red{ \tt{solution}}$

GIVEN -

AB = EF, BC = DE

AB PERPENDICULAR TO BD

FE PERPENDICULAR TO CE

TO PROVE -

∆ABD ~= ∆FEC

PROOF -

IN ∆ABD AND ∆FE

AB = EF

BC = DE

/_B = /_ E = EACH 90° (GIVEN)

${ \tt{by \: sas \: congruency}}$

∆ABD ~=∆EFC