Question

Pls answer with explanation.




Thank you.

Answer 1

Given:

• In Δ ABC, AD bisects ∠A
• AD⊥BC

To Find:

• Is ΔADB≅ΔADC and why
• Is BD = DC and why

Solution:

In Δ ABD and Δ ACD

   ∠BAD=∠CAD (∴ AD bisects ∠A)

     AD=AD  (common)

    ∠ADB=∠ADC (AD⊥BC)

∴ ΔADB≅ΔADC (ASA rule)

BD=DC (C.P.C.T)