Question

pls answer with full method. the 6th one ,,,,, "please "

Answer 1

a.√2916 = 54. this is not surprising since the radicand (2916) ends with 16, the desired integer square root ends in 4, and when looking at 29, the nearest (lesser) square root of that is 5, so that suggests we try 54--which is correct
c.√9025=95 . this is not surprising since the radicand (9025) ends with 25, the desired integer square root ends in 5, and when looking at 90, the nearest (lesser) square root of that is 9, so that suggests we try 95--which is correct

SIMILARLY e PROBLEM CAN BE SOLVED.IF IT WAS USEFULL HELP ME....