pls answer with steps (Q2)
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√3x^2-8x+4√3
√3x^2-6x-2x+4√3
√3x(x-2√3)-2(x-2√3)
(√3x-2)(x-2√3)
=√3x-2=0. or x-2√3=0
= x=2/√3 or x= x 2√3
Hope you understand
plz mark as brainliest
√3x^2-6x-2x+4√3
√3x(x-2√3)-2(x-2√3)
(√3x-2)(x-2√3)
=√3x-2=0. or x-2√3=0
= x=2/√3 or x= x 2√3
Hope you understand
plz mark as brainliest
Vatsal99:
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