Math, asked by Evraj, 1 year ago

pls answers this question

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Answered by yash1067
4
This is your question answer
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Evraj: thanks
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Answered by ishwarsinghdhaliwal
7

x = 5 - 2 \sqrt{6}  \\  \frac{1}{x}  =  \frac{1}{5 - 2 \sqrt{6}  }  \times  \frac{5  +  2 \sqrt{6}}{ 5  + 2 \sqrt{6} }  =  \frac{ 5  +  2 \sqrt{6} }{25 - 24}  = 5  + 2 \sqrt{6} \\ x +  \frac{1}{x}  = 5 - 2 \sqrt{6}  + 5 + 2 \sqrt{6}  \\  x +  \frac{1}{x} \: = 10 \\ squring \: on \: both \: sides \\ (x +  \frac{1}{x}) ^{2}  \: = 10 ^{2}  \\ x ^{2} +   \frac{1}{x ^{2} }  + 2 = 100 \\ x ^{2} +   \frac{1}{x ^{2} } = 100 - 2 \\ x ^{2} +   \frac{1}{x ^{2} } = 98

Evraj: thanks but I had already got answer
ishwarsinghdhaliwal: ok
ishwarsinghdhaliwal: wlc
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Evraj: pls answers my next question
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