Math, asked by kushikutty9, 1 year ago

pls answrr fast possess ​

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Answered by AmbikeshArman
1

sec(a) + 1 + sec(a) - 1 \div  {sec}^{2} (a) - 1

2sec(a) \div  {tan}^{2} (a)

2cosec(a)cot(a)

Answered by sohil88
0

[(secA+1)+(secA-1)]/sec^2A-1

2secA/tan^2A

2(1/cosA)/sin^2A/cos^2A

2(1/sinA)(cosA/sinA)

2cosecAcotA

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