Question

pls anwer now any one quick

Answer 1

We know that volume of the cylinder = pir^2h.

The volume of the 1st cylinder v1 = pir1^2h

The volume of the 2nd cylinder = pir2^2h

Now,

$\frac{pir1^2h}{pir2^2h} = \frac{3}{4}$

$\frac{r1^2}{r2^2} = \frac{3}{4}$

$\frac{r1}{r2} = \frac{9}{16}$


Therefore the ratio of their volumes = 9:16.


Hope this helps!