Question

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Answer 1

Answer:

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Answer 2

(i) Given polynomial is

$p(x)=4x^2−3x+7$

We need to find value of polynomial at x=1.

Then put the value of x=1 in the given polynomial, we get

$p(x)=4(1)^2−3(1)+7$

⇒p(x)=4×1−3×1+7

⇒p(x)=4−3+7

⇒p(x)=11−3=8

So, value of polynomial is 8.

$\small \bold{(ii) Given, q(y)=2y^2−4y+ \sqrt{11} }$

We need to find value of polynomial at y=1

Put the value y=1 in the given polynomial, we get

$q(y)=2(1)^2−4(1)+ \sqrt{11}$

$⇒q(y)=2−4+ \sqrt{11}$

⇒q(y)=2−4+3.32

⇒q(y)=1.32

Therefore, q(y)=1.32

(iii) We substitute the variable t=p the given

$\small \bold{polynomial \: r(t)=4t^4+3t^3−t^2+6 \: as \: follows:}$

$\bold{r(p)=4p^4+3p^3−p^2+6}$

Hence, the value of the given polynomial

$\small \bold{with \: t=p \: is \: r(p)=4p^4+3p^3−p^2+6.}$

$\bold{(iv) Given, s(z)=z^3 −1}$

We need to find value of given polynomial at z=1.

Put the value z=1, we get

$s(z)=(1)^3−1$

⇒s(z)=1−1

⇒s(z)=0

So, value is s(z)=0.

$\small\bold{(v) \: Given, \: p (x)=3x^2+5x-7 }$

Thus,

$\small\bold{p (x)=3(1)^2+5(1)-7 }$

=3+5-7

=1

(vi) Given,

$\small\bold{q(z)=5z^3−4z+ \sqrt{2} \: and \: z=2}$

On putting z=2, we get

$q(2)=5(2)^3−4(2)+ \sqrt{2}$

$\bold{⇒q(2)=5×8−4×2+ \sqrt{2}}$

⇒q(2)=40−8+1.41

⇒q(2)=33.41