Question

pls anwer this question.its urgent.​

Answer 1

Answer:

here

Explanation:

Given,

e=1.6×10

−19

C, I=4.8 A

Let number of electrons per second be n.

The current is defined as rate of flow of charge,

I=

t

q

Hence

q=n×e

Therefore, I=

t

n×e

Substituting values,

4.8 =n×1.6×10

−19

Hence, n=

1.6×10

−19

4.8

=3×10

19

electrons per second.

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Answer 2

A current of 4.8A is flowing in a conductor. Calculate the number of electrons passing per second.

Answer:

3 x 10¹⁹

Explanation:

Current = charge/time

             = n.e/time  

* where n is the number of electrons and e is the charge on each electron.

Let there are n electrons. In 1 sec:

In the given question :

 4.8 = n.e/1

  4.8 = n (1.6 x 10⁻¹⁹)

  4.8/(1.6 x 10⁻¹⁹) = n

  (4.8/1.6) x 10¹⁹ = n

   3 x 10¹⁹ = n

Hence 3 x 10¹⁹ electrons pas.s every second