Question

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Answer 1

since the circuit is connected parallel...

the equivalent resistance 1/R.eq=1/R1+1/R2+1/R3

1/R.eq=1/5+1/10+1/30

Taking Lcm we get:-

1/R.eq= 6+3+1

_____________

30

1/R.eq=10/30=1/3

therefore R.eq=3ohm

i) thus effective resistance is 3ohm

ii) current in ammeter= V/R (since V=IR)

I = 10/3= 3.33.....ampere

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