Question

pls anyone answer this question and do not write ans directly
solve only (vi) part

Answer 1

$\frac{x}{2} - \frac{y}{3} = \frac{1}{6} + y \\ \\ \frac{x}{2} - \frac{y}{3} - y - \frac{1}{6} = 0 \\ \\ \frac{3x - 2y - 6y - 1}{6} = 0 \\ \\ 3x - 8y - 1 = 0$