Question

pls anyone can do this question?????!!!!​

Answer 1

Answer:

yeah but condition is s that

u have to follow me

Answer 2

Step-by-step explanation:

sin(A)+sin(B) = 2sin(A+B)/2 cos(A-B)/2

sin(A)- sin(B) = 2sin(A-B)/2 cos(A+B)/2

The R.H.S. can be written as

$( \sin( \frac{\pi}{8} + \frac{a}{2}) + \sin( \frac{\pi}{8} - \frac{a}{2} ) ) \times$

$( \sin( \frac{\pi}{8} + \frac{a}{2}) - \sin( \frac{\pi}{8} - \frac{a}{2} ) = >$

$(2 \sin( \frac{\pi}{8}) \cos( \frac{ - a}{2} ) ) (2 \cos( \frac{\pi}{8} ) \sin( \frac{a}{2} ))$

cos(-x) =>cos(x)

$= > (2 \cos\frac{\pi}{8} \sin\frac{\pi}{8})(2 \sin( \frac{a}{2} \cos( \frac{a}{2} ) ) = >$

2 sin(a) cos(a) = sin(2a)

$\sin( \frac{\pi}{4} ) \sin(a) = > \frac{1}{ \sqrt{2}} \sin(a)$

Hence proved.Hope it helps you.