Pls anyone factorise 16y^4-81
Answers
Answered by
11
Answer:
This is u r answer......by using a²-b²=(a+b)(a-b)
Step-by-step explanation:
16y⁴-81 = (4y²)²-(9)²
= (4y²-9)(4y²+9)
= [(2y)²-(3)²](4y²+9)
= (2y-3)(2y+3)(4y²+9)
Answered by
0
Answer:
Since both terms are perfect squares, factor using the difference of squares formula,
a 2 − b 2 = ( a + b ) ( a − b )
where a = 4 y 2 and b = 9
( 4 y 2 + 9 ) ( 2 y + 3 ) ( 2 y − 3 )
Step-by-step explanation:
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