Question

pls anyone help me out in this question
I would be great full if u just give an appropriate figure​

Answer 1

Answer:

hey...Reema

Step-by-step explanation:

Let AO=H

CD=OB=60m

A'B=AB=(60+H)m

In ∆AOD,

tan30°=AO/OD=H/OD

H=OD/√3

OD=√3H

Now in ∆A'OD,

tan60°=OA'/OD=(OB+BA')/OD

√3=(60+60+H)/√3H

=(120+H)/√3H

=> 120+H=3H

2H=120

H=60m

Thus height of the cloud above water surface is

AB+A'B

= 60+60

=120m

Thankuuu...

mark as brainliest ...

good luck for maths...

Answer 2

Step-by-step explanation:

Answer:

hey...Reema

Step-by-step explanation:

Let AO=H

CD=OB=60m

A'B=AB=(60+H)m

In ∆AOD,

tan30°=AO/OD=H/OD

H=OD/√3

OD=√3H

Now in ∆A'OD,

tan60°=OA'/OD=(OB+BA')/OD

√3=(60+60+H)/√3H

=(120+H)/√3H

=> 120+H=3H

2H=120

H=60m

Thus height of the cloud above water surface is

AB+A'B

= 60+60

=120m

I hope it's help you!!