Question

Pls anyone help me with this question.​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

$\frac{3x + 2}{6x + 7}$

$given \: that \\ \\ f(x) = \frac{1}{3x + 2} \\ \\ so \: that \\ we \: can \: compair \: f(x) = f(f \: (x) \\ f \: \: (f(x) \: \\ \\ = \frac{1}{3.f(x) + 2} \\ = \frac{1}{3. \frac{1}{3x + 2} + 2} \\ = \frac{1}{ \frac{3 + (3x + 2).2}{3x + 2} } \\ = \frac{1}{ \frac{3 + 6x + 4}{3x + 2} } \\ = \frac{3x + 2}{6x + 7}$

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