Question

pls anyone solve thsi i will mark BRAINLIST

Answer 1

hi friend this is your answer
a)Because their values are given at timet=0, they are referred to as initial values. Our problem, usually called an "initial value problem", is to determine the velocity function and the positionfunction from the given accelerationfunction and the two initial values.
b)If the position of an object is a function x(t) , then the acceleration is: ... Since the derivative of a function at a given point is the slope of the function at that point, the velocity of an object is the slope of the displacement function and the acceleration of an object is the slope of the velocity function.
c)Instantaneous Formulasv(t) = s'(t)               a(t) = v'(t) = s"(t)Where v(t) is the first derivative of the position function and a(t)is the first derivative of the velocity function.  Also note it is the second derivative of the position function!!
d)Find the velocity function and the acceleration function for the function  s(t) = 2t3 + 5t - 7Solution:  Use the instantaneous formulasv(t) = s'(t) = 6t2 + 5a(t) = v'(t) = 12tb)  Find the velocity and acceleration at t = 2 for the above function.Solution:  Simply replace t with 2 in the above formulasv(2) = 6(4) + 5 = 29a(2) = 12(2) = 24
I hope it is helpful.