Question

pls anyone tell me the answer to the question in the picture​

Answer 1

Answer:

here's your answer ......................

Answer 2

Answer:

first join that point to the circle centre

let the external point be T

centre be O

and two tangents be P and Q respectively.

Now, In triangle TPO and TQO

angle P = angle Q = 90° ( Theorem 10 . 1)

TO = TO ( Common)

PO = QO ( radius of the circle )

hence TPO is congruent to TQO

TP = TQ (cpct)

hence proved

please mark my answer as brainliest.