Question

pls anyone tell me this question ​

Answer 1

$\large\underline\blue{\bold{Given \: Question :- }}$

• Speed of ball is 10 m/ sec. for 4 seconds and just at 4 seconds, it hits a wall and come back.

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$\begin{gathered}\begin{gathered}\bf To \: Find = \begin{cases} &\bf{Draw \: velocity \: time \: graph} \\ &\bf{Distance \: covered} \\ &\bf{Displacement} \end{cases}\end{gathered}\end{gathered}$

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$\large\underline\green{\bold{Solution :- }}$

$\blue{\bold{ Speed \: of \: ball = 10 m/ sec}}$

$\red{\bold{ Time \: taken = 4 sec}}$

☆We know,

$\large\underline\purple{\bold{Distance = Speed × Time }}$

$\blue{\bold{Distance \: travelled \: in \: first \: 4 \: sec. = 10 × 4 = 40 m}}$

☆So,

$\green{\bold{Distance \: travelled \: in \: next \: 4 \: seconds = 40 m.}}$

$\bf \:  ⟼ \purple{\bold{Total \: Distance \: travelled = 40 + 40 = 80 m}}$

$\bf \:  ⟼ \blue{\bold{Total \: displacement \: = 0}}$

$\blue{\bold{as \: the \: ball \: return \: to \: the \: starting \: point}}$

$\begin{gathered}\begin{gathered}\bf Hence = \begin{cases} &\sf{Find \: attachment \: of \: velocity \: time \: graph} \\ &\sf{Distance \: covered=80 \: m} \\ &\sf{Displacement = 0} \end{cases}\end{gathered}\end{gathered}$

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Answer 2

Answer:

$\large\underline\blue{\bold{Given \: Question :- }}$

Speed of ball is 10 m/ sec. for 4 seconds and just at 4 seconds, it hits a wall and come back.

─━─━─━─━─━─━─━─━─━─━─━─━─━

$\begin{gathered}\begin{gathered}\bf To \: Find = \begin{cases} &\bf{Draw \: velocity \: time \: graph} \\ &\bf{Distance \: covered} \\ &\bf{Displacement} \end{cases}\end{gathered}\end{gathered}$

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$\large\underline\green{\bold{Solution :- }}$

$\blue{\bold{ Speed \: of \: ball = 10 m/ sec}}$

$\red{\bold{ Time \: taken = 4 sec}}$

☆We know,

$\large\underline\purple{\bold{Distance = Speed × Time }}$

$\blue{\bold{Distance \: travelled \: in \: first \: 4 \: sec. = 10 × 4 = 40 m}}$

☆So,

$\green{\bold{Distance \: travelled \: in \: next \: 4 \: seconds = 40 m.}}$

$\bf \:  ⟼ \purple{\bold{Total \: Distance \: travelled = 40 + 40 = 80 m}}$

$\bf \:  ⟼ \blue{\bold{Total \: displacement \: = 0}}$

$\blue{\bold{as \: the \: ball \: return \: to \: the \: starting \: point}}$

$\begin{gathered}\begin{gathered}\bf Hence = \begin{cases} &\sf{Find \: attachment \: of \: velocity \: time \: graph} \\ &\sf{Distance \: covered=80 \: m} \\ &\sf{Displacement = 0} \end{cases}\end{gathered}\end{gathered}$

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