Question

pls anyone tell the answer of 8 till 14..pls tell fast as possible ..if anyone knows any 1 answer also then pls send

Answer 1

8.In triangle EBC and triangle DCB
EC=BD [GIVEN]
Angle BEC=Angle BDC=90°
BC is common for both
Therefore triangle BCE&CBD are congruent [R.H.S]
Angle DCB= Angle EBC [c.p.c.t]
9.
I will send the others tomorrow.
Now i am going to sleep

Answer 2

Q.12}
AB || DC ...Given
AD || BC ...Given
opposite sites are equal and BD is common side between ∆ABD & ∆DCB
therefore, By SSS congruency
∆ABD ~= ∆DCB
hence proved.