Question

pls ASAP. plssssssssssssss​

Answer 1

Go through the solution, it may help you. Have a nice day

Answer 2

First take the left hand limit.

$\quad$

$\displaystyle\begin {aligned}\lim_{x\to1^-}f(x)&=\lim_{x\to1^-}(a+bx)&\quad\quad[\because\ f(x)=a+bx,\quad x\ \textless\ 1]&\\\\\\f(1)&=a+b(1)&&\\\\\\4&=a+b&\quad\longrightarrow\quad (1)&\end{aligned}$

$\quad$

Then take the right hand limit.

$\quad$

$\displaystyle\begin {aligned}\lim_{x\to1^+}f(x)&=\lim_{x\to1^+}(b-ax)&\quad\quad[\because\ f(x)=b-ax,\quad x\ \textgreater\ 1]&\\\\\\f(1)&=b-a(1)&&\\\\\\4&=b-a&\quad\longrightarrow\quad (2)&\end{aligned}$

$\quad$

On solving (1) and (2), we get,

$\quad$

$\large\text{ \underline {\underline {a=0\quad;\quad b=4}} }$