Question

Pls calculate the n- factor of this reaction

P4 + OH- ----> PH3 + H2PO2

THANK YOU☺️☺️


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Answer 1

Explanation:

elemental phosphorus is both oxidized and reduced…

14P4+3H++3e−→PH3Reduction: P(0) → P(-III):

But basic conditions were specified…so we add three equiv hydroxide to each side…

14P4+3H2O+3e−→PH3+3HO−Oxidation: P(0) → P(-III):

14P4+2HO−→P(OH)+2+3e−Oxidation: P(0) → P(+III):

Note that you got the wrong charge in your question…

We add the oxidation reaction to the reduction equation to get…

12P4+3H++2HO−→P(OH)+2+PH3

And we clean this up to get…

12P4+H++2H2O→P(OH)+2+PH3

…which I think is balanced with respect to mass and charge