Question

pls can anyone slove this its urgent​

Answer 1

Draw AP⊥ CB extended

∠ABP = 180°-150° = 30°

ΔAPB is a right angled triangle right angled at P

$Sin30^o = \frac{AP}{AB}$

$\frac{1}{2} =\frac{AP}{6}$

$AP = 3$ cm

Area(ΔABC) = $\frac{1}{2}*AP*BC$

                    = $\frac{1}{2}*3*8$

Area(ΔABC) = 12 cm²

HOPE IT HELPS!!