Math, asked by bhavanap088, 1 month ago

pls can anyone solve this question I am facing problem in this question​

Attachments:

Answers

Answered by kiran12355
1

Step-by-step explanation:

a) 4xy,5yz,9xz

=4xy*5yz*9xz

=180x^2y^2z^2

=180*(1)^2*(-1)^2*(2)^2

=180*1*1*4

=720

b)2x,3y,4z,-5xyz

=2x*3y*4z*(-5xyz)

=-120x^2y^2*z^2

= -120*(1)^2*(-1)^2*(2)^2

= -120*4

= -480

c)(-4/5x^2y^3),3xy,(-4x^2y)

=(-4/5)*3*(-4)*x^(2+1+2)*y^(3+1+1)

=(48/5)*x^5*y^5

=(48/5)*(1)^5*(-1)^5

=(48/5)*1*(-1)

= -48/5

d)(-4)*(1/2)xy*(-3/4)x

=(-4)*(1/2)*(-3/4)*x^2y

=(12/8)*(1)^2(-1)

= -3/2

Similar questions