Math, asked by senguptaanshul, 7 months ago

pls can anyone solve this sum chap- Indices​

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Answered by suhail2070
0

Answer: m = 1+ n

 \frac{ {3}^{2n} . {3}^{2} . {3}^{n}  -  {3}^{3n} }{ {3}^{3m} . {2}^{3} }  =  \frac{1}{ {3}^{3} }  \\  \\   \frac{ {3}^{3n + 2} -  {3}^{3n}  }{ {3}^{3m} }   =  \frac{ {2}^{3} }{ {3}^{3} }  \\  \\    \frac{ {3}^{3n}( {3}^{2 } - 1)  }{ {3}^{3m} }  =  {( \frac{2}{3} )}^{3}  \\  \\  \\  \\  \frac{8}{ {3}^{3m - 3n} }  =  {( \frac{2}{3} )}^{3}  \\  \\  \\  \\  {( \frac{1}{ {3}^{m - n} } )}^{3}  =   {( \frac{1}{3} )}^{3}  \\  \\  {3}^{m - n}  =  {3}^{1}  \\  \\ m - n = 1 \\  \\ m = 1 + n

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