Question

pls can you answer the question ​

Answer 1

$hello$

Question:-

Solve for x

$x - (2x - \frac{3x - 4}{7} ) = \frac{4x - 27}{3} - 3$

Answer:-

$x - (2x - \frac{3x - 4}{7} ) = \frac{4x - 27}{3} - 3\\ \\ = x - 2x + \frac{3x - 4}{7} = \frac{4x - 27}{3} - 3 \\ \\ = - x + \frac{3x - 4}{7} = \frac{4x - 27}{3} - 3 \\ \\ = \frac{ - 7x + 3x - 4}{7} = \frac{4x - 27 - 9}{3} \\ \\ = \frac{ - 4x - 4}{7} = \frac{4x - 36}{3} \\ \\ = 3( - 4x - 4) = 7(4x - 36) \\ \\ = - 12x - 12 = 28x - 252 \\ \\ = - 12x - 28x = - 252 + 12 \\ \\ = - 40x = - 240 \\ \\ < x = 6 >$