Question

pls clarify my doubt

Answer 1

Answer:

The right answer is 50.

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Answer 2

Question :

$\frac{1}{2 \sqrt{6} - 5}$

Concept :

Rationalisation

• To rationalize the denominator, you must multiply both the numerator and the denominator by the conjugate of the denominator. Remember to find the conjugate all you have to do is change the sign between the two terms.

• Distribute (or FOIL) both the numerator and the denominator.

Solution :

$\frac{1}{2 \sqrt{6} - 5}$

$\frac{1(2 \sqrt{6} + 5)}{(2 \sqrt{6} - 5)( 2\sqrt{6} + 5) }$

By using identity for the denominator : (a - b)(a + b) = a² - b²

Here,

a → 2√6

b → 5

$\frac{2 \sqrt{6} + 5}{ {(2 \sqrt{6}) }^{2} - {(5)}^{2} }$

$\frac{2 \sqrt{6} + 5 }{24 - 25}$

$\frac{2 \sqrt{6} + 5}{ - 1}$

As it's -ve in the denominator so -1 will be multiplied by 2√6+5

$\frac{ - 1(2 \sqrt{6} + 5)}{1}$

$\small - 2 \sqrt{6} - 5$

So the answer is -2√6-5