pls derive the relation between power and velocity by ease
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Answered by
7
Hola User_______________
Here is Your Answer....!!!
________________________
Actually welcome to the concept of the Work , Power And Energy .....
Basically we know that .....
Power = Work done ÷ time ......
now we that .... Work = Force x displacement. ....
Since here The force is constant ......
there fore. ...... differentiate the displacement with respect to time we get. .,,
Power = Force × ds/dt
since ...ds/dt = velocity .....
there fore ...e.
Power = Force x Velocity....
Here is Your Answer....!!!
________________________
Actually welcome to the concept of the Work , Power And Energy .....
Basically we know that .....
Power = Work done ÷ time ......
now we that .... Work = Force x displacement. ....
Since here The force is constant ......
there fore. ...... differentiate the displacement with respect to time we get. .,,
Power = Force × ds/dt
since ...ds/dt = velocity .....
there fore ...e.
Power = Force x Velocity....
chinnaben:
i dont know how to differentiate
Answered by
1
power = work / time
d(power) = d(work) / d(time)
[add integration on both sides]
d(power) = d ( force vector . displacement vector ) / d(time)
power = force vector . d (displacement vector)
/ d(time)
[ power and force vector are constant & d(time) is divided only for d (displacement) ]
power = force vector . velocity vector
[ d (displacement) / d (time) = velocity vector ]
here only dot product is present not cross product
d(power) = d(work) / d(time)
[add integration on both sides]
d(power) = d ( force vector . displacement vector ) / d(time)
power = force vector . d (displacement vector)
/ d(time)
[ power and force vector are constant & d(time) is divided only for d (displacement) ]
power = force vector . velocity vector
[ d (displacement) / d (time) = velocity vector ]
here only dot product is present not cross product
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