Question

Pls derive the relationship between Kp and Kc.

Class 11 Chapter Equilibrium

Answer 1

think aA+bB+......=lL+mM+......
then we can used the laws
you will get the ans on the picture

Answer 2

Heya !
_____

_______________________________________________________
★Relationship between Kp and Kc ★
_______________________________________________________

=> Kc - Equilibrium Constant is the ratio of product of molar concentration of products to the reactant .

•°• Kc = { C }^c { D }^d / { A }^a { B }^b -------------( 1 )

Also ,

°•° Kp = { P C }^c { P D }^d / { P A }^a { P B }^b---------(2)

★ We know that for an Ideal Gas , PV = NRT ✔

=> P = NRT/V [ °•° c = n/v ]

=> P = CRT ✔

~Substitute this value in the equation ,

=> Kp = { CRT }^c { DRT}^d / {ART}^a {BRT}^b

( Take RT common factor )

=> Kp = { P C }^c { P D }^d / { P A }^a { P B }^b {RT}^c+d/{RT}^a+b

( The expression = Kc and c + d - a + b = ∆n )

=> Kp = Kc RT^∆n
================

Thus this is the required relation between them!!

$....$

________________________________________________________