Pls derive the relationship between Kp and Kc.
Class 11 Chapter Equilibrium
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think aA+bB+......=lL+mM+......
then we can used the laws
you will get the ans on the picture
then we can used the laws
you will get the ans on the picture
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raghavi98:
Thanks lot to u
Answered by
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Heya !
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★Relationship between Kp and Kc ★
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=> Kc - Equilibrium Constant is the ratio of product of molar concentration of products to the reactant .
•°• Kc = { C }^c { D }^d / { A }^a { B }^b -------------( 1 )
Also ,
°•° Kp = { P C }^c { P D }^d / { P A }^a { P B }^b---------(2)
★ We know that for an Ideal Gas , PV = NRT ✔
=> P = NRT/V [ °•° c = n/v ]
=> P = CRT ✔
~Substitute this value in the equation ,
=> Kp = { CRT }^c { DRT}^d / {ART}^a {BRT}^b
( Take RT common factor )
=> Kp = { P C }^c { P D }^d / { P A }^a { P B }^b {RT}^c+d/{RT}^a+b
( The expression = Kc and c + d - a + b = ∆n )
=> Kp = Kc RT^∆n
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Thus this is the required relation between them!!
________________________________________________________
_____
_______________________________________________________
★Relationship between Kp and Kc ★
_______________________________________________________
=> Kc - Equilibrium Constant is the ratio of product of molar concentration of products to the reactant .
•°• Kc = { C }^c { D }^d / { A }^a { B }^b -------------( 1 )
Also ,
°•° Kp = { P C }^c { P D }^d / { P A }^a { P B }^b---------(2)
★ We know that for an Ideal Gas , PV = NRT ✔
=> P = NRT/V [ °•° c = n/v ]
=> P = CRT ✔
~Substitute this value in the equation ,
=> Kp = { CRT }^c { DRT}^d / {ART}^a {BRT}^b
( Take RT common factor )
=> Kp = { P C }^c { P D }^d / { P A }^a { P B }^b {RT}^c+d/{RT}^a+b
( The expression = Kc and c + d - a + b = ∆n )
=> Kp = Kc RT^∆n
================
Thus this is the required relation between them!!
________________________________________________________
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