Question

PLS DIFFERENTIATE THIS EQUATION WITH FORMULA AND STEPS

PLS DON'T TRY IF U CAN'T FULL FILL THE ABOVE CONDITIONS

Answer 1

Answer:

Step-by-step explanation:

Using chain rule of differentiation which says that if a function is-:

y(x)=f(x)×g(x)

Then-:

y'(x) = f(x)g'(x)+g(x)f'(x)

Therefor -:

$e^{x}.sinx.lgox= sinx.logx.e^{x} + e^{x} .logx.cos x+e^{x}.sinx.1/x$