Question

pls divide


very urgent

Answer 1

2y-8)2y^2-14y+24(y-3

2y^2-8y

____________

-6y+24

-6y+24

_____________

0

Answer 2

${\huge {\mathfrak {\red {Answer :-}}}}$

2y^2 - 14y + 24

= 2( y^2 - 7y + 12)

= 2(y^2 - 3y - 4y + 12)

=2{ y(y-3) - 4(y-3)}

= 2(y-4)(y-3)

= (2y - 8)(y - 3)

Now, (2y - 8)(y - 3) / (2y - 8)

= (y - 3)

$<b>$ REGARDS, ARNAB ✌️

THANK YOU