Math, asked by latchagadossk, 1 year ago

pls divide


very urgent

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Answers

Answered by zeus6
1

2y-8)2y^2-14y+24(y-3

2y^2-8y

____________

-6y+24

-6y+24

_____________

0

Answered by arnab2261
1

 {\huge {\mathfrak {\red {Answer :-}}}}

2y^2 - 14y + 24

= 2( y^2 - 7y + 12)

= 2(y^2 - 3y - 4y + 12)

=2{ y(y-3) - 4(y-3)}

= 2(y-4)(y-3)

= (2y - 8)(y - 3)

Now, (2y - 8)(y - 3) / (2y - 8)

= (y - 3)

 <b> REGARDS, ARNAB ✌️

THANK YOU


latchagadossk: which i should consider
latchagadossk: as correst answer
latchagadossk: *correct
arnab2261: my one,. ☺️
latchagadossk: while multiplying 2 (y-4)(y-3)= (2y-8)(2y-6)
latchagadossk: but ur multiplying 2 only by (y-4)
arnab2261: ya,.
arnab2261: 2*3*5 = 6*5
latchagadossk: i can't understand
arnab2261: 2 * 3 * 5 = (2 * 3) * 5 = 6 * 5.
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