Pls do 26th question !!
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DRAW A PERPENDICULAR ON SIDE BC NAME THE POINT E
SO, BE = EC ( ALTITUDE ACT AS A MEDIAN N AN EQUILATERAL )
AE = (a)( ROOT 3/2 ) ( AE is the altitude)
BD = BC/4 (GIVEN)
DE = BC/4
NOW by pythagoras theorem
AD2 = AE2 + DE2
substitutin value
AD2 = (aroot3/2)2 + (BC/4)2
AD2 = 3a2/4 + BC2/16
AD2 = (12a2 + BC)/16
16AD2 = 12a2 + BC2 (BC = AB = AC = a)
16AD2 = 13BC2
Hence proved
SO, BE = EC ( ALTITUDE ACT AS A MEDIAN N AN EQUILATERAL )
AE = (a)( ROOT 3/2 ) ( AE is the altitude)
BD = BC/4 (GIVEN)
DE = BC/4
NOW by pythagoras theorem
AD2 = AE2 + DE2
substitutin value
AD2 = (aroot3/2)2 + (BC/4)2
AD2 = 3a2/4 + BC2/16
AD2 = (12a2 + BC)/16
16AD2 = 12a2 + BC2 (BC = AB = AC = a)
16AD2 = 13BC2
Hence proved
vinipan:
Prove that 16AD^2 =13BC^2
see solved :)
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What I have to prove???
Prove that 16AD^2 =13BC^2
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Please do it fast
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