Math, asked by nishuthakur73519, 7 months ago

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find the value of a and b​

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Answered by veerkiri007
5

Answer:

a. In ΔXYX with external point P.

.: angle PXY + YXZ = 180° (linear pair)

.: 137° + angle a =180°

.: a = 180 - 137

.: a = 43° or angle YXZ = 43°

Now,

In ΔXYZ,

.: angle xyz + yzx + zxy = 180° ( angle sum. property)

xyz + 74°+ 43° = 180°

b + 117° = 180°

b = 180 - 117

b = 63°

.: a =43°

and, b = 63°

hence prove.

d. In Δ XYX ,with external line P and Q in which P is on YZ and Q is on XY.

Here,

angle XYZ = PYQ ( vertically opposite angle)

.: XYZ = 90° or a = 90°

Now,

XYZ + YZX + ZXY = 180 (angle sum property)

.: 90 + b + 32° = 180°

.: b + 122° = 180°

.: b = 52°

so,

a = 90°

b = 52°

hence prove.

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Answered by himanshivashisht75
0

Step-by-step explanation:

SUM OF ALL THE SIDES OF TRIANGLE = 180

1.

  • a = 180 - 74
  • a = 106
  • b = 106 - 74
  • b = 32

2.

  • a = 180 - 32
  • a = 148
  • b = 148 - 32
  • b = 116

HERE IS YOUR ANSWER

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