Question

pls do answer correctly don't just spam ⚠️⚠️⚠️​

Answer 1

From question,

Both the resistance are in series thus, the total resistance will be;

• Resistance of conducter + Resistance of bulb
• 6 + 30
• 36 $\Omega$

And the voltage is 9 volt.

Now, it is simple from here, remember that ohm's law? yes, we are going to use that formula here;

• V = IR
• 9 = I × 36
• 9/36 = I
• 1/4 = l
• 0.25 A = l

Therefore, the current flowing through the conductor is 0.25 A.

And thus,option c) 0.25 A is correct.

______________________

Thank youu!! :))

Answer 2

From question,

Both the resistance are in series thus, the total resistance will be;

Resistance of conducter + Resistance of bulb

6 + 30

36 \text{\O}megaØmega

And the voltage is 9 volt.

Now, it is simple from here, remember that ohm's law? yes, we are going to use that formula here;

V = IR

9 = I × 36

9/36 = I

1/4 = l

0.25 A = l

Therefore, the current flowing through the conductor is 0.25 A.

And thus,option c) 0.25 A is correct.

______________________

Thank youu!! :))