Question

pls do it and help me out

Answer 1

Step-by-step explanation:

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Answer 2

${ \underline{ \underline{\sf{\red{ \bigstar \: Solution \: to \: question \: 1 : }}}}}$

Given:

• the length of the room is 6m
• breadth of the room is 4m

To Find:

• the area of the following room

Solution:

→ here we have got the length and breadth of the room and we have to find the area with the following dimensions

$\purple{ \underline { \mathfrak{As \: we \: know \: that \dag}}}$

$\blue \bigstar{ \underline{ \boxed{ \pink{ \mathfrak{ area \: of \: a \: rectangle =l \times b}}}}}$

Where,

• ➪ L stands for${ \bf{\pink{length}}}$
• ➪ B stands for${ \bf{\pink{breadth}}}$

let's use the following values in the formula now,

${ : \implies} \sf \pink{ area_{(rectangle)}} \: = l \times b \\ \\ \\ { : \implies} \sf \pink{ area_{(rectangle)}} \: =( 6 \times 4) {m}^{2} \\ \\ \\ \:{ : \implies} \sf \pink{ area_{(rectangle)}} = 24 {m}^{2}$

$\therefore \:{ \underline{ \sf{ \: the \: area \: of \: the \: room \: is \: 24 {m}^{2} }}}$

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${ \underline{ \underline{\sf{\red{ \bigstar \: Solution \: to \: question \: 2 : }}}}}$

Given:

• Length of the sheet 22cm
• width of the sheet is 5cm

To Find:

• the area of the sheet?

Solution:

→ here we have got the length and breadth of the room and we have to find the area with the following dimensions

$\purple{ \underline { \mathfrak{As \: we \: know \: that \dag}}}$

$\blue \bigstar{ \underline{ \boxed{ \pink{ \mathfrak{ area \: of \: a \: rectangle =l \times b}}}}}$

where,

➪ L stands for${ \bf{\pink{length}}}$

➪ B stands for${ \bf{\pink{breadth}}}$

let's use the following values in the formula now,

$\longrightarrow \sf\blue{ area_{(rectangle)}} = l \times b \: \: \: \\ \\ \\ \longrightarrow \sf\blue{ area_{(rectangle)}} = \: 22 \times 5 \\ \\ \\ \longrightarrow \sf\blue{ area_{(rectangle)}} = 110cm ^{2}$

$\therefore \:{ \underline{ \sf{ \: the \: area \: of \: the \: paper \: is \:110 {cm}^{2} }}}$

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${ \underline{ \underline{\sf{\red{ \bigstar \: Solution \: to \: question \: 3: }}}}}$

Given:

• Side of a square Is 7cm

To Find:

• area of the square?

Solution:

→ here we have got the of the room and we have to find the area with the following dimensions

$\purple{ \underline { \mathfrak{As \: we \: know \: that \dag}}}$

$\blue \bigstar{ \underline{ \boxed{ \pink{ \mathfrak{ area \: of \: a \: rectangle =s \times s}}}}}$

Where,

• ➪ S stands for ${ \bf{\pink{Side}}}$

let's use the following values in the formula now,

→ Area = side²

→ Area = 7²

→ Area = 49cm²

$\therefore \:{ \underline{ \sf{ \: the \: area \: of \: the \: square \: is \:49 {cm}^{2} }}}$

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${ \underline{ \underline{\sf{\red{ \bigstar \: Solution \: to \: question \: 4: }}}}}$

Given:

• Side of the chessboard is 30cm

To Find:

• perimeter and area

Solution:

❖ We know,

• perimeter of a square = 4 × side

→ Perimeter = 4 × 30cm

→ Perimeter = 120cm

• area of a square = side²

→ area = 30²

→ area = 900cm²

$\therefore \:{ \underline{ \sf{ \: the \: area,perimeter \: of \: the \: square \: area \:120cm,900 {cm}^{2} }}}$

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