Question

pls do it fast
need urgently

Answer 1

HELLO !!!!!!!!!!!

so first what we need to do is :

Let a = 1, b = 8, c = 125 and d = 343 are the four odd perfect cube numbers.

Now ∛a=∛1=1,∛b=∛8=2,∛c=∛125=5  and ∛d=∛343=7                    

 (∛a+∛b)^2 (∛c  ∛d) be 192, 360, 512, 576 and 600.

g.c.d (192, 360, 512, 576, 600) = 8

 ∴ 8 is always a factor of  (∛a+∛b)^2 (∛c+∛d) where a, b, c and d are four  perfect cube numbers.