pls do it step by step
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simran298:
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See u need to take prime factors of it
108 can be written as 27*4= 3*3*3*2*2
As it is cube root u need to make triplets
now for a raised to power four= a*a*a*a
for b raised to power 3= b*b*b
Therefore cube root of 3*3*3*2*2*a*a*a*a*b*b*b
= 3ab∛4a
108 can be written as 27*4= 3*3*3*2*2
As it is cube root u need to make triplets
now for a raised to power four= a*a*a*a
for b raised to power 3= b*b*b
Therefore cube root of 3*3*3*2*2*a*a*a*a*b*b*b
= 3ab∛4a
23 one
this will be done in the following ways
okay thx
just instead of triplets make quartlets of nos.
for ex b raised to power 6= b*b*b*b*b*b now there is 1 pair of quartlet
so this can be expressed as b* 4th root of b raised to power 2
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